Further toy refinement
If N is an odd constant (odd, as in N = 2k+1), when does this happen?
(N - 1) / 2 = i (mod 2i + 1)
... then let's see how he does, up there, without all the assistance!
If N is an odd constant (odd, as in N = 2k+1), when does this happen?
(N - 1) / 2 = i (mod 2i + 1)
Posted by
Andrés
at
07:48
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